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Step count in the \

, If the answers with step-counting principles, step by step when they bring \Cases of 14 different balls into 3 boxes, each box has at least put a ball How many laws? Wrong solution: Step 1, from 4 balls of any check box 3 into 3 , a kind of release method; Step 2, the remaining 1 small ball into a box either, there Aj species put method. Therefore, to meet the requirements placed above the law put a kind of analysis method appeared to repeat. In fact, if set up 4 balls were A, B, C, D, the first one box to get in step 1 A, respectively, the remaining two boxes are B, C, D placed in Step 2 to 1 boxes, when the points system is IADI, IBI, IC 『. Step 1 and in turn release the D, B, C, step 2 into 1 of the A box, when the points system is lDAl, IB 『, ICI, the two put the first one for the box method, A first emerged after the D and D after the first A different order, but placed after the result is the same. Here, \From the above analysis, there are two methods for each put the ball in a box in the case, it is repeated every 1 put France first, with the \Usually combined solution is to first order, that is, on the same box in the first two elements into one element, and then together with the other two elements for the three elements of the full array. Therefore AI = 36 species. Cases of 2100 products in 98 of the qualified, two defective products from a random selection of 100 of the three, at least one is defective pumping methods How many? Wrong solution: Step 1, from the two defective in any of pumping a,[link widoczny dla zalogowanych], kind of pumping method; Step 2, the remaining 99 items from any of pumping two, there. Types of pumping method;. . Placed to meet the requirements of the law is cg9 = 9702 species. Analysis of selected two defective duplication of the pumping method. Such as: Step 1 taken to the defective A, step 2, B and qualified drawn to the defective product, then remove the IABal,[link widoczny dla zalogowanych], and if step 1 is taken to B, is extracted in step 2 A and a , then remove the {BAaI, similar to Example 1, the two pumping method after the first A and first B Ba Aa is not the same after, but after taking the results are the same. From the above analysis, taking the case of two defects were calculated twice. The two extraction methods for the defective pumping, with the exclusion may be the right answer for the C5. A 8 = 9604 kinds. Often used method of elimination or classification methods, sub-species of Mexican-style c a qs9604,[link widoczny dla zalogowanych], or c = 9604 species. , \ Cases of 36 different books, divided into 3 parts, the number of seed law? Wrong solution: Step 1, from 6 optional two different books, there are ways ci; Step 2, from Choose the remaining 2 of 4 books, a kind of method; Step 3, the remaining two, and as a group, there are C; ways. Therefore, to meet the requirements of sub-law is q species. Analysis of error lies in the separation of the 3 groups of the whole order. If you set the six different types of books as A, B, C, D, E, F, Step 1 Remove the A, B, Step 2 Remove the C, D, Step 3 Remove the E, F get group is lABI, lcDI, IEFI. If Step 1 take c, D, obtained in step 2 A, B,[link widoczny dla zalogowanych], Step 3 Remove the E, F, by grouping or ICDl, IABl, IEFI. In fact, one of the other steps in each group are likely to occur again, but as a group is the same. From the above analysis,[link widoczny dla zalogowanych], the results should be of the above \